• Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.


New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback


(propose a free ad)

Site Statistics

202 submissions , 160 unreviewed
4,981 questions , 2,140 unanswered
5,340 answers , 22,629 comments
1,470 users with positive rep
813 active unimported users
More ...

Recent questions tagged magnetic-monopoles

A magnetic monopole is a hypothetical particle with only one magnetic pole. Predicted by certain modern theories, including string theory, supergravity, and various grand unified theories. The origin of the idea can be traced back to Maxwell's equations, which allow for the existence of magnetic monopoles

Gauss's law for magnetism states that:

$$\nabla\cdot\vec B=0$$ Whereas the corresponding law for electricity states that: $$\nabla\cdot\vec E=\frac{q_e}{\epsilon_0}$$ Thus the hypothesis of magnetic monopoles might be stated as "non-divergenceless magnetic fields exist", i.e. Gauss's law for magnetism would take the form $\nabla\cdot\vec B=\frac{q_m}{\epsilon_0}$ for a new "magnetic charge" $q_m$.
+ 1 like - 0 dislike
2 answers 498 views
+ 1 like - 0 dislike
0 answers 641 views
+ 2 like - 0 dislike
0 answers 283 views
+ 2 like - 0 dislike
2 answers 353 views
+ 7 like - 0 dislike
1 answer 1220 views

user contributions licensed under cc by-sa 3.0 with attribution required

Your rights