• Register
PhysicsOverflow is a next-generation academic platform for physicists and astronomers, including a community peer review system and a postgraduate-level discussion forum analogous to MathOverflow.

Welcome to PhysicsOverflow! PhysicsOverflow is an open platform for community peer review and graduate-level Physics discussion.

Please help promote PhysicsOverflow ads elsewhere if you like it.


New printer friendly PO pages!

Migration to Bielefeld University was successful!

Please vote for this year's PhysicsOverflow ads!

Please do help out in categorising submissions. Submit a paper to PhysicsOverflow!

... see more

Tools for paper authors

Submit paper
Claim Paper Authorship

Tools for SE users

Search User
Reclaim SE Account
Request Account Merger
Nativise imported posts
Claim post (deleted users)
Import SE post

Users whose questions have been imported from Physics Stack Exchange, Theoretical Physics Stack Exchange, or any other Stack Exchange site are kindly requested to reclaim their account and not to register as a new user.

Public \(\beta\) tools

Report a bug with a feature
Request a new functionality
404 page design
Send feedback


(propose a free ad)

Site Statistics

174 submissions , 137 unreviewed
4,308 questions , 1,640 unanswered
5,089 answers , 21,602 comments
1,470 users with positive rep
635 active unimported users
More ...

  Multiparticle Quantum Mechanics with independent phases

+ 0 like - 0 dislike

I am pondering a variant of quantum mechanics, where each particle actually has, loosely speaking, 'its own' complex phase. A two-particle wave-function would thus be written as e.g.

$\psi(x,y)=e^{i_x x p_1 }e^{i_y y p_2 }$

where $i_x$ and $i_y$ are independent. $\psi$ thus takes values not in $\mathbb C$, but rather in  $\mathbb C \otimes_{\mathbb R}\mathbb C$. The tensor product has to be taken over $\mathbb R$, otherwise the 'effect' obviously vanishes.

A two particle state now contains more (local) phase information than in the standard. I have not done any strict calculations, but surprisingly it does not seem to make much difference for actual systems like the Helium atom or for scattering experiments.

What differences would there be to standard QM? (I have not been able to find any paper of a similar approach or calculation)

asked May 12, 2016 in Theoretical Physics by NUU (0 points) [ no revision ]

Please log in or register to answer this question.

user contributions licensed under cc by-sa 3.0 with attribution required

Your rights