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  "Color charge" of the adjoint fermion?

+ 1 like - 0 dislike
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What kind of "color charge" does the adjoint fermion carry?

Let us consider the SU(N) gauge theory. The gauge field is in the adjoint representation (rep).

Well-Konwn: If the fermion is in SU(N) fundamental rep, we know the fermions will form a color multiplet of N-component. For $N=3$, we say that there are 3 colors (r,g,b) of a given fermion $\psi$ $$ (\psi_r, \psi_g, \psi_b) $$

  1. However, if the fermion is in SU(N) adjoint rep, we know the fermions will form a color multiplet of (N$^2-1)$-component. For N=3, we say that there have 8-component of color multiplet. So,

    What kind of "color charge" does each component of adjoint fermion carry? There should be 8 different choices. $$ (\psi_1, \psi_2, \dots, \psi_{8}) $$ What does the 1,2,3, $\dots$, 8 stand for in terms of color indices?

  2. Are the color charges of adjoint fermions organized the same way as the gluons (which are also in adjoint) as in https://en.wikipedia.org/wiki/Gluon#Color_charge_and_superposition? Does both the adjoint fermions carry a color and an anti-color just as a gluon does? Why is that?

  3. How can we read this information of color charges from the adjoint Rep of $SU(3)$ Lie algebra?


p.s. we may say the 8 gluons carry 8 distinct color anti-color pairs: $$ (r\bar{b}+b\bar{r})/\sqrt{2}, -i(r\bar{b}-b\bar{r})/\sqrt{2}, (r\bar{g}+g\bar{r})/\sqrt{2} $$ $$ -i(r\bar{g}-g\bar{r})/\sqrt{2},(b\bar{g}+g\bar{b})/\sqrt{2},-i(b\bar{g}-g\bar{b})/\sqrt{2} $$ $$ (r\bar{r}-b\bar{b})/\sqrt{2},(r\bar{r}+b\bar{b}-2g\bar{g})/\sqrt{6} $$ And how about the 8-multiplet of adjoint fermions? What color charge do they carry?

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user annie marie heart
asked Feb 18, 2018 in Theoretical Physics by annie marie heart (450 points) [ no revision ]
retagged Nov 5

1 Answer

+ 2 like - 0 dislike

An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ab} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators. The Dirac operator acts as a covariant derivative in the adjoint representation $$ (D_\mu \psi)^A = (\partial_\mu \delta^{AB}+igf^{ACB}A^C_\mu)\psi^B $$
just like it acts on gluons.

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user Thomas
answered Feb 18, 2018 by tmchaefer (280 points) [ no revision ]
Then (1) how would you write the Dirac Lagrangian for it? and (2) what will be the charge for each $\psi^A$? Thanks

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user annie marie heart
Your subindices do not match somehow.

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user annie marie heart
@ Thomas, I am curious: (i) How would you associate the color charge to the fermions? (ii) And what will be the distinctions for Majorana and Dirac fermions?

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user wonderich
how about this, experts? physics.stackexchange.com/questions/387330 ? thanks.

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user annie marie heart
@wonderich i) the color charge is fixed by the coupling to the gauge field, as given in the answer, ii) the fermions can be either Majorana or Dirac, but in contrast to the fundamental rep a single Majorana fermion is already anomaly free.

This post imported from StackExchange Physics at 2020-11-05 13:28 (UTC), posted by SE-user Thomas

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