# Can two particles remain entangled even if one is past the event horizon of a black hole?

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Can two particles remain entangled even if one is past the event horizon of a black hole? If both particles are in the black hole?

What changes occur when the particle(s) crosses(cross) the event horizon?

I have basic Physics knowledge, so I request that answers not assume an in-depth understanding of the field. Thank you all in advance!

This post imported from StackExchange Physics at 2016-01-04 12:59 (UTC), posted by SE-user ThisIsNotAnId
in both cases measurements are impossible, hence, even if we come up with some sensible argument about what should happen, its slightly outside of the realm of science. And i say 'slightly' because this conclusion is based on our current understanding of black holes.

This post imported from StackExchange Physics at 2016-01-04 12:59 (UTC), posted by SE-user lurscher
@lurscher: This is not completely true, since we can study model black holes in AdS/CFT.

This post imported from StackExchange Physics at 2016-01-04 12:59 (UTC), posted by SE-user Ron Maimon

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This question is the black hole information paradox. If you take two entangled particles, make a black hole by colliding two highly energetic photons, throw in one of the two entangled particles, and wait for the black hole to decay, is the remaining untouched particle entangled with anything anymore?

In Hawking's original view, the infalling particle would no longer be in communication with our universe, and the entanglement would be converted to a pure density matrix from our point of view. The particle outside would no longer be entangled with anything we can see in our causal part of the universe. Then when the black hole decays, the outgoing Hawking particles of the decay would not be entangled with the untouched particle.

This point of view is incompatible with quantum mechanics, since it takes a pure state to a density matrix. It is known today to be incorrect, since in models of quantum gravity when AdS/CFT works, the theory is still completely unitary.

This means that the particle stays entangled with something as its partner crosses the horizon. This "thing" is whatever degrees of freedom the black hole has, those degrees of freedom that make up its entropy. When the black hole decays completely, the outgoing particles are determined by these microscopic variables, and at no point was there ever a loss of coherence in the entanglement.

This point of view requires that the information about the particle that fell through the horizon is also contained in the measurable outside state of the black hole. This is t'Hoofts holographic principle as extended into Susskind's black hole complementarity, the principle that the degrees of freedom of a black hole encode the infalling matter completely in externally measurable variables. This point of view is nearly universal today, because we have model quantum gravity situations where this is clearly what happens.

The details of the degrees of freedom of a four dimensional neutral black hole in our universe are not completely understood, so it is not possible to say exactly what the external particle is entangled with as the infalling particle gets to the horizon. But the basic picture is that the infalling particle doesn't fall through from the external point of view, but smears itself nonlocally on the horizon (like a string theory string getting boosted and long). The external particle is still entangled with this second representation of the infalling particle.

This means that the same thing is described in two different ways, the interior and the exterior. But since no observer measures both at the same time, it is consistent with quantum mechanics to just have a unitary transformation that reconstructs the interior states from those states of the exterior that can be measured at infinity by scattering experiments.

This post imported from StackExchange Physics at 2016-01-04 12:59 (UTC), posted by SE-user Ron Maimon
answered May 15, 2012 by (7,720 points)

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