# Connection between Grabert formalism and the Zwanzig (1980)/Grabert-Hänggi-Talkner projector

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The Grabert formalism as developed in  seems to be quite general, and it is possible to restate f.e. the Mori  or Mazur-Oppenheim  formalism in Grabert's theory (i.e. one can find relevant probability densities for both cases which result in the right projector / the right generalised Langevin equation).

In chapter 4, section 2 of  , a generalised Fokker-Planck equation is derived (following in principle  or ) and it is claimed, that the projector

$\mathbf{P}X(\Gamma)=\int d\alpha\ \frac{tr\{\rho_\beta \psi_\alpha X\}}{p_\beta(\alpha)}\psi_\alpha(\Gamma)$

could also be derived from Grabert's projector with a special relevant probability density $\overline{\rho}(t)$ (see eq. 4.2.1 in ).

However, I'm unable to reproduce this result. The task seems simple, as it should be only a substitution into a given formula.

Could someone familiar with Grabert's work explain the method to derive this particular projector in Grabert's formalism? Thanks.

 H. Grabert: Projection Operator Techniques in Nonequilibrium Statistical Mechanics

 H. Mori: Transport, Collective Motion, and Brownian Motion; Prog. Theor. PHys. 33,p. 423

 P. Mazur, I. Oppenheim: A molecular theory of Brownian motion; Physica 50,2,p.241

 R. Zwanzig: Problems in nonlinear transport theory; in Systems Far from Equilibrium / Lecture Notes in Physics Vol. 132, p. 198

 Grabert et al.: Microdynamics and nonlinear stochastic processes of gross variables; J. Stat. Phys. 22,5,p.537

edited Jul 25, 2014

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Prof. Grabert was so kind to point out the derivation.

The relevant probability density of eq. 4.1.10

$\bar{\rho}(\Gamma,t)=\rho_\beta(\Gamma)\int d\alpha\ \frac{p(\alpha)}{p_\beta(\alpha)}\Psi_\alpha(\Gamma)$

is linear in the "mean values" $p(\alpha)$.

Going back to the original definition of the Grabert projection operator

$\mathbf{P}[a]F=\rm{tr}\{\bar{\rho}F\}+\sum_i(A_i-a_i)\rm{tr}\{(\partial_i\bar{\rho})F\}$,

the projection operator simplifies to

$\mathbf{P}[a]F=\sum_iA_i\rm{tr}\{\frac{\partial\bar{\rho}}{\partial a_i}F\}$,

because the relevant probability density satisfies

$\bar{\rho}=\sum_ia_i\frac{\partial\bar{\rho}}{\partial a_i}$

due to its linearity in the mean values.

$\frac{\partial\bar{\rho}}{\partial a_i}$ is in our case the variational derivative with respect to $p(\alpha)$ and therefore equal to

$\rho_\beta(\Gamma)\frac{1}{p_\beta(\alpha)}\Psi_\alpha(\Gamma)$.

It remains to convert the particular projection operator above to the relevant variables used (i.e. $A_i\rightarrow \Psi_\alpha(\Gamma), a_i\rightarrow p(\alpha),\sum_i \rightarrow\int d\alpha,$ and the Zwanzig/GHT-projector follows.

answered Jul 25, 2014 by (80 points)

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