I am referring to this, http://home.web.cern.ch/about/updates/2014/04/lhcb-confirms-existence-exotic-hadron
So how does this work if we stick to keeping quarks in the 3 dimensional fundamental representation of SU(3)?
This bound-state seems to have 2 anti-quarks and 2 quarks. So with just 3 colours how do we make the whole thing anti-symmetric with respect to the colour quantum number?
Is there anything called "anti-colour" quantum number that an anti-quark can posses so that there are a total of (3x2)^2 colour options to choose from for the 2 quarks and 2 anti-quarks? I have never heard of such a thing!
The point is that unlike the U(1) charge, the non-Abelian charge doesn't occur in the Lagrangian for the quarks. The Lagrangian only sees the different flavours, the gauge groups and the gauge coupling constant.
This post imported from StackExchange Physics at 2014-04-13 14:30 (UCT), posted by SE-user user6818