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What is the sense of introducing generating functional to the summands of expansion of S-matrix?

+ 4 like - 0 dislike

Let's have generating functional $Z(J)$: $$ Z(J) = \langle 0|\hat {T}e^{i \int d^{4}x (L_{Int}(\varphi (x)) + J(x) \varphi (x))}|0 \rangle , \qquad (1) $$ where $J(x)$ is the functional argument (source), $\hat {T}$ is the chronological operator, $\varphi (x)$ - some field.

I want to understand the reasons for its introduction for the summands of expansion of S-matrix. As I read in the books, it helps to consider only the vacuum expectation values​​, forgetting about in- and out-states. But in $(1)$ appear summands like $\int \frac{J(p)dp}{p^2 - m^2 + i0}$ instead of the contributions from external lines. It may refer to the internal lines. So what to do with them and are there some other reasons to introducing $(1)$ except written by me?

This post imported from StackExchange Physics at 2014-03-24 04:01 (UCT), posted by SE-user Andrew McAddams
asked Nov 27, 2013 in Theoretical Physics by Andrew McAddams (340 points) [ no revision ]
Comment ot the question (v2): For a connection between off-shell correlation functions and on-shell S-matrix elements, see LSZ reduction formula.

This post imported from StackExchange Physics at 2014-03-24 04:01 (UCT), posted by SE-user Qmechanic

2 Answers

+ 4 like - 0 dislike

The primary utility in introducing the generating functional is in using it to compute correlation functions of the given quantum field theory.

Let's restrict the discussion to that of a theory of a single, real scalar field on Minkowski space, and let $x_1, \dots, x_n$ denote spacetime points. Of central importance are time-ordered vacuum expectation values of field operators evaluated at such points; \begin{align} \langle0|T[\phi(x_1)\cdots\phi(x_n)]|0\rangle. \end{align} It can be shown that these objects can be obtained from the generating functional by taking functional derivatives with respect to the $J(x_i)$ as follows: \begin{align} \langle0|T[\phi(x_1)\cdots\phi(x_n)]|0\rangle = \frac{1}{Z[0]}\left(-i\frac{\delta}{\delta J(x_1)}\right)\cdots \left(-i\frac{\delta}{\delta J(x_n)}\right)Z[J]\Bigg|_{J=0}. \end{align} This standard fact is proven in many books on QFT. It's often proven using the path integral approach which makes it pretty transparent why it's true. The crux of the argument is that every time you take a functional derivative with respect to the source $J(x_i)$, it pulls down a factor of the field $\phi(x_i)$. Dividing by $Z[0]$ is an important normalization relating to vacuum bubbles, and setting $J=0$ after computing the appropriate functional derivatives eliminates terms with more than $n$ factors of the field and renders the final result source-independent as it should be.

This post imported from StackExchange Physics at 2014-03-24 04:01 (UCT), posted by SE-user joshphysics
answered Nov 27, 2013 by joshphysics (830 points) [ no revision ]
+ 3 like - 0 dislike

If you can calculate vacuum-to-vacuum transition amplitudes, you can calculate S-matrix elements, because the two are related by the LSZ reduction formula. The LSZ will in any case chop off the propagators for external lines that the generating functional inserts, so you will end up only needing to compute amputated diagrams.

This post imported from StackExchange Physics at 2014-03-24 04:01 (UCT), posted by SE-user lionelbrits
answered Nov 28, 2013 by lionelbrits (110 points) [ no revision ]

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