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  Max induction of spring with two colliding trains

+ 0 like - 2 dislike

Two trains collide, train A weights 15.000 kg and moves with 10km/u (2.77... m/s) to the right, the other train weights 30.000kg and moves with 20km/u (5.55m/s) to the left. Train A has a spring on its right side with k=3MN/m. What is the max induction of that spring?
I know it has something to do with T1 +V1 = T2 V2, but I'm confused because the spring is moving too.

Closed as per community consensus as the post is not graduate-level
asked Jan 30, 2018 in Closed Questions by anonymous [ no revision ]
recategorized Aug 26, 2018 by Dilaton

This is not graduate-level, voting to close. 500 rep users please upvote the closevote here.

1 Answer

+ 0 like - 0 dislike

Found it myself, First I had to look what the result of the two trains collision would be. (ma*va1+mb*vb1 = (ma+mb)*v2) and then I could fill in the T1 + V1 = T2 + V2 formula with T1 = 1/2*ma*va² + 1/2*mb*vb² and V1 = 0 since s1 of the spring is. And T2 = 1/2*(ma+mb)v2² and V2=1/2*k*smax².
Resulting in smax = 0.4809 meters.

answered Jan 30, 2018 by anonymous [ no revision ]

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