# Gravitational energy emitted as gravitational waves from GW170814

+ 2 like - 0 dislike
830 views

According with https://arxiv.org/pdf/1105.0265.pdf it is possible to consider a binary system of black holes as a  "Gravitationally Equivalent of an Atom (GEA)".

The energy level $E_1$ of the GEA ground state is given by where $G$ is the gravitational constant, $M_1$ and $M_2$ are the masses of the two black holes and $h_b$ is the Planck constant.

Assuming that for the  system GW170814 :   $M_1 = 31M_{Sol}$ and $M_2 = 25M_{Sol}$ ; then we obtain

$$E_1 = -0.5181806117 × 10 ^{206} J$$

We claim that the total gravitational energy emitted as gravitational waves due to the formation of  GW170814 is

$$0.5181806117 × 10 ^{206}J$$.

Do you agree?

L+Virgo annouced 2.4 to 3.1 solar mass energy which is about $5 . 10^{47} J$

One of the many assumptions of the document is about the BH configuration : relative point-like nucleus , a small ensemble of nuclei and a classical gravitational bound. This means that if GW170814 was an atom-like of this kind, we would get a crazy first energy level. This shows that the comparison doesn't hold.

Hi @igael, many thanks for your comment.  You are right, "L+Virgo annouced 2.4 to 3.1 solar mass energy which is about 5 x 1047J"  but the question is how such quantity was determined.  I think that such quantity was not obtained experimentally.  Such quantity was obtained as a difference between the sum of the  masses of the original black holes (31+25 = 56) and the mass of the final black hole (53); 56 - 53 = 3 solar masses.  Then, the quantity  5 x 1047was obtained assuming that GW170814 is a simple black hole but the astronomical observations do not discard the possibility that GW170814 be a gravitational atom and then the quantity 0.5181806117×10206is not actually excluded.  Do you agree?  All the best.

@Juancho : hi:) is not this calculus valid only for a size 0 black hole nucleus with some atoms around ? Such E1 is higher than the universe mass estimation by a factor of $10^{104}$ !

@Juancho: you pointed an interesting thing, we must check 1105.0265 :)

+ 1 like - 0 dislike

Other possibility is as follows.

We assume that  the total gravitational energy emitted as gravitational waves due to the formation of  GW170814 is given by  $-E_{1}$ where and G is the gravitational constant, M1 and M2 are the masses of the two black holes and $h_b$ is the gravitational  Planck constant.  In order to compute the value of $h_b$ we assume that Then we obtain it is to say

$$h_b = 0.1035899036 × 10^{46} J-s$$

Using such value we deduce that the frequency of the gravitational wave emitted due to the formation of  GW170814 is $82.50898602$ hertz.  The corresponding period is $0.01211989200$ seconds and the corresponding  wave length is $3635.967600$ Km.

Do you agree?

Similar computations can be performed for GW150914 and GW170104 and the obtained results are very good approximations to the observed values.

answered Sep 30, 2017 by (1,130 points)
edited Oct 1, 2017 by juancho

 Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead. To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL. Please consult the FAQ for as to how to format your post. This is the answer box; if you want to write a comment instead, please use the 'add comment' button. Live preview (may slow down editor)   Preview Your name to display (optional): Email me at this address if my answer is selected or commented on: Privacy: Your email address will only be used for sending these notifications. Anti-spam verification: If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:p$\hbar$ysi$\varnothing$sOverflowThen drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds). To avoid this verification in future, please log in or register.