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Stirring condensate with two lasers, one shortly behind the other, one sin(x), other -sin(x)

+ 0 like - 2 dislike

If you sent a laser with superposition of sine and negative sine, they'd cancel.  Two beams with sin(x) followed very closely by -sin(x), stirring a condensate would create quantum vortices.  The closeness of the beams would mean that there would be a chance for the two lasers to annihilate at any point along the path into the condensate.  If you create a lattice with the beams, they would be cancelling in a quantum way, creating random paths for photons to travel.  If you draw the function sin(x) and -sin(x) on the graph, rotate the graph, and reproduce the same sin(x) and -sin(x) to the left and right of that wavy up and down curve.  The point where the two humps meet is the tube of a torus where photons travel up and down.  But they can also travel up a tube between the two touching humps and go left or right.  Now reproduce many to the left and right and into the paper, and you have the black hole scrambler.  The fact that some are flashing on and off, is denying pathways randomly for photons, and opening paths for the photons.  The benefit is that if you send a train of paired entangled photons into the condensate, the scrambler will give you entanglements of any subgroup, so large entanglements are possible, as shown in Malcedena,  Susskind, "Cool Horizons of Entangled Black Holes", where the essence of the black hole is its ability to scramble or do this to entangled pairs

Closed as per community consensus as the post is [CLOSED]
asked May 19 in Closed Questions by t686 (-30 points) [ no revision ] 1 flag
recategorized Jul 13 by Dilaton

blocked after 4 unsuccessful warnings.

This does not ask anything, voting to close.

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1 Answer

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I thought about it and consider for simplicity a lattice of lasers in the condensate, all the ones on one diagonal sine, the crossing beams on the off-diagonal negative sine.  If a laser outside is fired at a crossing so that a detector is only registered a particular superposition of sine and -sine, at the detection time it forces the two beams which made that superposition at that node, it forces it.  Another beam outside fired at another node will at the exact same time of the other detection, register a different superposition, and that forces the sine and negative sine beams as well.  Firing on all nodes of a particular superposition at each node from outside beams to detection points at the same time should cause a quantum superposition or stretching-shrinking of all the fixed diagonal and off diagonal beams of sine and -sine so that all those detections happen.  The detectors linked to the outside beams can also vary continuously in time so that if you're trying to find the lowest energy of something I presume it's simply a matter of dialing the outside beams until the lowest energy state is found.  I assume for simplicity that all this can be done at the exact same time due to the fixed beams in the condensate being quantum.  Of course lasers I don't think I fixed in the condensate would work that way but rather it would be a lattice of atoms.  Perhaps the original question of sine followed closely by negative sine stirrers would create such a superposition state in the lattice of atoms created from the stirring and that the above procedure of firing from outside beams at all lattice points, each point predestined by the detectors to be registered at a particular superposition at the same time would be simply a matter of continuously varying the particular detection superposition points in time, linked to the outside lasers, until the lowest energy state is found.  The lowest energy state is probably actually linked to the original two beams stirrer in that continuously varying the two beams in a pattern while initially stirred is the quantum algorithm which is solved by continuously varying the outside beams -in no patterrn- until there is intelligent output in the answer.  The two beam stirrer is sine followed by the second beam of negative sine.  However it would be those two functions but imagine them to be two cars with one able to accerate or decelerate relative to the other, so that the initial algorithm would be the relative positions of sine and negative sine as produced by the laser so it could imprint the algorithm into the lattice. And I assume all those outside firings don't disturb the original imprint because the lattice is a chain of vortices produced by the stirring, and vortices are persistent.

answered May 20 by t686 (-30 points) [ revision history ]
edited May 20 by t686

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