# Regge behavior of the 1342 ordering of the Veneziano amplitude

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I'm trying to understand the Regge limit of the following open string diagram,

$\frac{\Gamma(-1-\alpha' s)\Gamma(-1-\alpha' u)}{\Gamma(-2-\alpha'(s+u))}$

The other diagrams I understand fine and lead to the usual Regge behavior, $(1+\exp(-i\pi \alpha' t))(\alpha' s)^{\alpha' t}$

But this diagram is confusing. We take s to infinity along a direction where the imaginary part of s goes to infinity. If we want to be right above the branch cut then we should go in the direction $s+i\epsilon s$

This gives $\frac{(-\alpha' s)^{-\alpha' s}(-\alpha' u)^{-\alpha' u}}{\Gamma(2+\alpha' t)}$

The phase of this is $\exp(i\pi \alpha' s)$

At this point all the old dual resonance model papers say that this is exponentially suppressed, which I understand because the imaginary part of s is large. But what about when we go back to the physical region, where the imaginary part of s is zero? Then this seems to give a nonvanishing result, which modifies the standard Regge answer. Any ideas on why this is wrong?

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