# Electronic configuration for singlet and triplet states

+ 0 like - 0 dislike
230 views

Is there a difference in the electronic configuration for singlet and triplet states? For example, He atom has 1s2 configuration in its ground state (singlet state)

But what about when the He atom is excited. It can come in both states (Signlet and Triplet)

Can I tell from the excited electronic configuration whether the atom is in a singlet or a triplet state?

Thanks!

This post imported from StackExchange Physics at 2014-04-13 12:28 (UCT), posted by SE-user Haneen Su

+ 1 like - 0 dislike

I am not sure that I get your question right, but let me try to answer according to my understanding.

The spin part of the two electron wave function of the singlet state $|0,0\rangle=|l=0,m=0\rangle$ is

$|0,0\rangle=(|\uparrow\downarrow\rangle-|\downarrow\uparrow\rangle)/\sqrt{2}$

The three triplet states look like this:

$|1,0\rangle=(|\uparrow\downarrow\rangle+|\downarrow\uparrow\rangle)/\sqrt{2}$

$|1,1\rangle=|\uparrow\uparrow\rangle$

$|1,-1\rangle=|\downarrow\downarrow\rangle$

If you are unfamiliar with the notation, $\uparrow$ denotes spin $+1/2$ and $\downarrow$ denotes spin $-1/2$; the numbers on the left denote: the total angular momentum $l$ of both electrons and its $z$ component $m$.

If the electrons are in the same energy state, they have to have different spins, that is, the state can be either $|0,0\rangle$ or $|1,0\rangle$, so in principle singlet and triplet are possible. If one of the electrons is excited, any of the four states is possible, since the spins don't have to be different any more. Therefore, if you know that both electrons have spin up or both have spin down, you can be sure, that it is a triplet state. If one spin is up and the other down, you cannot tell from the spin configuration whether it is a singlet or a triplet, since again both $|0,0\rangle$ or $|1,0\rangle$ are possible.

This post imported from StackExchange Physics at 2014-04-13 12:28 (UCT), posted by SE-user Photon
answered Apr 12, 2014 by (70 points)
I'd suggest using $\uparrow$ and $\downarrow$ instead of $+$ and $-$ to denote spins, otherwise they look too mixed up when adding and subtracting kets.

This post imported from StackExchange Physics at 2014-04-13 12:28 (UCT), posted by SE-user Ruslan
I was too lazy to look up the TeX commands for them and didn't know them by heart, to be honest.

This post imported from StackExchange Physics at 2014-04-13 12:28 (UCT), posted by SE-user Photon
\uparrow and \downarrow

This post imported from StackExchange Physics at 2014-04-13 12:28 (UCT), posted by SE-user Ruslan
Thanks, edited.

This post imported from StackExchange Physics at 2014-04-13 12:28 (UCT), posted by SE-user Photon

 Please use answers only to (at least partly) answer questions. To comment, discuss, or ask for clarification, leave a comment instead. To mask links under text, please type your text, highlight it, and click the "link" button. You can then enter your link URL. Please consult the FAQ for as to how to format your post. This is the answer box; if you want to write a comment instead, please use the 'add comment' button. Live preview (may slow down editor)   Preview Your name to display (optional): Email me at this address if my answer is selected or commented on: Privacy: Your email address will only be used for sending these notifications. Anti-spam verification: If you are a human please identify the position of the character covered by the symbol $\varnothing$ in the following word:p$\hbar$ysics$\varnothing$verflowThen drag the red bullet below over the corresponding character of our banner. When you drop it there, the bullet changes to green (on slow internet connections after a few seconds). To avoid this verification in future, please log in or register.