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  Where and how exactly does string theory and Q.E.D. use zeta function regularization?

+ 5 like - 0 dislike
3237 views

In the video they mention it being used in many fields of physics inclusing String and QED theory.

But I remember reading somewhere that 1+2+3..=-1/12 is obviously a "mathematical trick" (something about stupidly equating incompatible sets), and if so, how does this turn out to be true for things that are real (like QED)?

This post imported from StackExchange Physics at 2014-03-26 12:48 (UCT), posted by SE-user laggingreflex
asked Mar 25, 2014 in Theoretical Physics by laggingreflex (50 points) [ no revision ]
retagged Mar 26, 2014
Watch the follow-up youtube.com/… and also youtube.com/watch?v=d6c6uIyieoo&feature=youtu.be and youtube.com/…

This post imported from StackExchange Physics at 2014-03-26 12:48 (UCT), posted by SE-user nephente

2 Answers

+ 2 like - 0 dislike

Zeta function regularization is used in other fields, and even in pure mathematics to obtain finite answers from otherwise divergent integrals. In bosonic string theory, the mass of states in lightcone gauge is,

$$M^2 = \frac{4}{\alpha'} \left[ \sum_{n>0} \alpha^{i}_{-n}\alpha^{i}_n + \frac{D-2}{2}\left( \sum_{n>0} n\right) \right]$$

where $\alpha'$ is the universal Regge slope, $D$ is the spacetime dimension, and $\alpha^{i}_n$ may be interpreted as Fourier coefficients of the expanded form of the embedding functions $X^{\mu}(\sigma)$ in the Polyakov action which provide a map from the worldsheet to the target space. We use the fact that

$$\sum_{n>0} n = 1+2+3+...=\zeta(-1)=-\frac{1}{12}$$

to write the expression for the mass of states as,

$$M^2 = \frac{4}{\alpha'} \left(N - \frac{D-2}{24} \right)$$

If we look at the ground state, corresponding to $N=0$, we see

$$M^2 = -\frac{1}{\alpha'}\frac{D-2}{6}$$

which corresponds to a particle with an imaginary mass, known as a tachyon. The demand that we preserve $SO(1,D-1)$ Lorentz symmetry forces us to choose that the first excited state $(N=1)$ be massless, and so we must choose the spacetime to be $D=26$. In other string theories, the critical dimension of the string may be lower, e.g. $10$ or $11$. For further details, I recommend Prof. Tong's lectures notes on string theory available at: http://www.damtp.cam.ac.uk/user/tong/string.html.

This post imported from StackExchange Physics at 2014-03-26 12:48 (UCT), posted by SE-user JamalS
answered Mar 25, 2014 by JamalS (895 points) [ no revision ]

And what happens with harmonic series ? we have $$ \sum_{n=1}^{\infty}n^{-1}= \gamma $ euler's constant but what would happen with $ \sum_{n=0}^{\infty}(n+a)^{-1} $

+ 1 like - 0 dislike

In addition to what JamalS said, there is also the Casimir energy in string theory.

\(\epsilon=-\frac12\left(D-2\right)\sum\frac1n\)

answered May 11, 2014 by dimension10 (1,985 points) [ revision history ]

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