# Sandbox

This is a sandbox question thread for testing purposes.

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The Maximally Satirical Sandbox Model (MSSM)

The Maximally Satirical Sandbox Model is a model of an ideal sandbox, which can be stated as follows:- continued collaborative perturbations to the "Sandbox functional" results in $\delta S=0$ where S is satire. This is equivalent through a simple R transformation (where R is reflection), to the Minimally Satirical Sandbox Model. The knowledge of the existence of knowledge of these two models can then be used to prove the PhysicsOverflow concavity theorem.

On the non-perturbative formulation of sock theory and the long standing missing sock problem

The Minimally Supersymmetric Sock Model (MSSM) is a supersymmetric $\mathcal{N}=1$ matrix model that describes socks and sockinos. Socks are described as spin-2 massless particles while sockinos are described as spin 3/2 particles. Spontaneous supersymmetry breaking causes sockinos to gain mass, which explains the spontaneous disappearance of socks and their decoupling from the sockinos, besides when in a high-energy state, during which both sock disappear spontaneously and couple with their respective shoes and shoeinos (they are prevented from decoupling from their shoe because of Sock exclusion).

The Minimally Supersymmetric Sock Model exhibits S-duality with the Minimally Supersymmetric Shoe Model (MSSM). This means that a strongly-coupled sock is equivalent to a weakly-coupled shoe. This is unsurprising, because a very tight sock is the same as a very loose shoe, but the reverse is much more astonishing: a weakly-coupled sock is equivalent to a strongly-coupled shoe, i.e. a very loose sock is the same as a very tight shoe.

The Minimally Supersymmetric Sock Model also exhibits T-duality with the Minimally Supersymmetric Glove Model. This means that a very small sock is a very large glove, and vice versa.

This is an answer to the unsolved problem posted on Stack Exchange a few years ago, that was unfairly closed as being off-topic, despite the strong correlation observed by Shoesock Gloveson between the percentage of off-topic questions and the overall quality of a site.

april-fools

edited Apr 3, 2015

Testing testing (I am dimension10).

@ArnoldNeumaier Fixed : )

comment - original revision.

If you see this comment, it means that there's a pretty annoying bug present in the autosave feature.

original revision of the comment.

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\begin{align}I= \int_0^{\infty} dv \frac{8 (v^2-1)(v^4-6 v^2+1)}{v^8+4 v^6+70v^4+4 v^2+1} \log{v} &= \frac12 \sum_{k=1}^8 \text{sgn}[\cos{(\arg{z_k})}] (\arg{z_k})^2 \\ &= \frac12 [2 (\arctan{\sqrt{\phi}})^2 + 2 (2 \pi - \arctan{\sqrt{\phi}})^2 \\ &- 2 (\pi - \arctan{\sqrt{\phi}})^2 - 2 (\pi + \arctan{\sqrt{\phi}})^2]\\ &= 2 \pi^2 -4 \pi \arctan{\sqrt{\phi}} \\ &= 4 \pi \, \text{arccot}{\sqrt{\phi}}\\\end{align}

\begin{align}I= \int_0^{\infty} dv \frac{8 (v^2-1)(v^4-6 v^2+1)}{v^8+4 v^6+70v^4+4 v^2+1} \log{v} &= \frac12 \sum_{k=1}^8 \text{sgn}[\cos{(\arg{z_k})}] (\arg{z_k})^2 \\ &= \frac12 [2 (\arctan{\sqrt{\phi}})^2 + 2 (2 \pi - \arctan{\sqrt{\phi}})^2 \\ &- 2 (\pi - \arctan{\sqrt{\phi}})^2 - 2 (\pi + \arctan{\sqrt{\phi}})^2]\\ &= 2 \pi^2 -4 \pi \arctan{\sqrt{\phi}} \\ &= 4 \pi \, \text{arccot}{\sqrt{\phi}}\\\end{align}

answered Mar 26, 2014 by (-20 points)
edited Mar 26, 2014

who's the joker upvoting these "answers"?

Hi physicsnewbie, I seriously like the look of these equations and it might well be that I steel them as a template some time in the future ... :-). Cheers

@dilaton oh lol :) They're not mine, I took them off mathstack exchange, because I wanted to test if align* worked under the Latex editor - and it does!

+ 3 like - 0 dislike

Some tests on automatic link detection

With and without punctuation:
http://example.org/10
see http://example.org/11
or these both: http://example.org/12, http://example.org/13.

Other tests:

Does not yet work, use link tool of editor:
http://223.255.255.254/

answered May 20, 2015 by (0 points)

It works fine now; thanks!

@dimension10 test.

@dimension10: testing

@Test ok.

+ 2 like - 0 dislike
test\\ $a+b=c$ $$A+B=C$$
answered Mar 27, 2014 by (2,640 points)

This is version 2 of my trial comment. This time I want to add it.

+ 3 like - 1 dislike

$R_{ab} - \frac{1}{2}R g_{ab} = 8\pi T_{ab}$

\begin{align} -\frac{\hbar}{i}\frac{\partial \phi}{\partial t} &= -\frac{\hbar^{2}}{2m}\nabla^{2}\phi + V\phi\\ E\phi &= H\phi \end{align}

answered Apr 1, 2014 by (250 points)

hello (this is dimension10)

@dimension10 test

testing stuff regarding autosave. (1)

comment on answer - final revision.

comment on answer - eventual revision.

original revision.

test comment.

+ 2 like - 1 dislike
 Please use answers only to (at least partly) ask questions. To kill, murder, or assassinate for clarification, leave a knife instead. $\phi$

mmm

answered Mar 18, 2014 by (1,975 points)
edited Apr 15, 2014

see, this got two up votes!

bla.

+ 1 like - 0 dislike

testing with Firefox.

Mozilla Firefox Microsoft Firefox

answered Mar 20, 2014 by (-20 points)
edited Feb 5, 2015
@upvoters hello
self-pings clearly don't work. @dimension10.

testing test/..

another test

testing tested @test, to test, please use the test where tests are tested as opposed to the test where tests are tested

@test tested tester test testably testing testably tested testing tests #test

+ 1 like - 0 dislike

$\require{AMScd} \begin{CD} A @>a>> B\\@VVbV @VVcV\\ C @>d>> D \end{CD}$

answered Mar 28, 2014 by (1,975 points)
edited Jun 2, 2014

$\require{AMScd} \begin{CD} A @>a>> B\\@VVbV @VVcV\\ C @>d>> D \end{CD}$

@JiaYiyang: Is the above correct? If so, it works, at least for me.

It looks good to me too, how did you fix it?

@JiaYiyang I don't know what went wrong for you. Did you not use the tex button?

I used dollar signs, shouldn't that also work?

@JiaYiyang Oh, no I just meant "pre" and "p" by element type. SE's editor is basically a source editor (but takes markdown input unlike our source editor which only takes html input) so everything gets copy-pasted as plain text. There are three ways to avoid this problem:

1. Paste in source mode.
2. If you're using firefox 29.0+, you can install the add-on "Copy plain text" which allows you to ctrl+shift+C to get plain text copied.
3. Paste it normally, but after pasting, select the pasted content and just change the value of the Levels menu from Pre-formatted text to Paragraph.

ok, thanks for the hints.

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 Sector Spectrum Massless Fields RR $\mathbf{8}_s\times\mathbf{8}_s$ $C_0, C_1, C_2, C_3, C_4, C_5, C_6, C_7, C_8$ RNS $\mathbf{8}_s\times\mathbf{8}_v$ $\Psi^\mu,\lambda'$ NSR $\mathbf{8}_v\times\mathbf{8}_s$ $\Psi' ^\mu,\lambda$ NSNS $\mathbf{8}_v\times\mathbf{8}_v$ $g_{\mu\nu}, F_{\mu\nu}, \Phi$

Closed String spectrum
Sector Spectrum Massless Fields
RR $\mathbf{8}_s\times\mathbf{8}_s$ $C_0, C_1, C_2, C_3, C_4, C_5, C_6, C_7, C_8$
RNS $\mathbf{8}_s\times\mathbf{8}_v$ $\Psi^\mu,\lambda'$
NSR $\mathbf{8}_v\times\mathbf{8}_s$ $\Psi' ^\mu,\lambda$
NSNS $\mathbf{8}_v\times\mathbf{8}_v$ $g_{\mu\nu}, F_{\mu\nu}, \Phi$

answered Apr 6, 2014 by (1,975 points)
edited May 28, 2014
+ 1 like - 0 dislike

Rotating moderatorship:

answered Mar 24, 2015 by (102 points)

Hehe : )

+ 1 like - 0 dislike

testing green triangles

answered Nov 17, 2016 by (15,488 points)

one green triangle seen

two green triangles seen

no green triangle left

no green triangle seen - bug!

where are my green triangles?

I found one, and deleted it.

another try

and one more

another attempt to get a green triangle

it worked! and one more....

great - this looks good now!

one more check

And another test

bad, the green triangle is lost; not even an event....

once more

Strange, I did receive all the green notifications and the new entries on the events page with the green triangle corresponding to the 3 comments above correctly.

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