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Water on tank 12m high, feeding pipe 200m long and 125mm diameter. Open end.

Given friction factor of 0.008 for the pipe and total of 3.2K for various fittings.

Asked to find water flow rate in Kg/s in the pipe.

Been looking at this for ages now and have got really confused!

So far :

As the tank and the outlet are open to the atmosphere we can use v= √2gh to find the velocity of the water?

V=√(2*9.81*12)

V=15.34m/s

Mass flow rate =pVA

Where p is the density of water 1000kg/m3

V is mean velocity 15.34m/s

A is cross sectional area normal to the direction of flow 0.125mXπ2

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m = 1000 x 15.34 x (0.125xπ2)

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