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QCD in the non-perturbative regime

+ 4 like - 0 dislike
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In the list of unsolved problems in physics.

  • Confinement: the equations of QCD remain unsolved at energy scales relevant for describing atomic nuclei. How does QCD give rise to the physics of nuclei and nuclear constituents?

  • Quark matter: the equations of QCD predict that a plasma (or soup) of quarks and gluons should be formed at high temperature and density. What are the properties of this phase of matter?

what is this means that "non-perturbative QCD are the exploration of phases of quark matter, including the quark-gluon plasma."?

This post imported from StackExchange Physics at 2014-08-29 16:49 (UCT), posted by SE-user Guest
asked Sep 2, 2013 in Theoretical Physics by Guest (20 points) [ no revision ]

2 Answers

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Due to asymptotic freedom, the perturbation series expansion of QCD breaks down at low energy. The expansion parameter, the coupling constant, becomes too large and therefore we cannot rely on results anymore. The value of the coupling constant approaches the order of $1$ at an energy of several hundred MeV, a scale referred to as $\Lambda_{QCD}$ ("Lambda-QCD"). Perturbation theory becomes reliable several GeV above this scale. But what does that mean for the so-called "QCD phase diagram", which is a diagram with temperature as the vertical and baryon chemical potential (or density, which might be easier to imagine) as the horizontal axis?

As you can see in the image in the other answer, there is a variety of interesting phenomena at a relatively low energy scale. This means that a perturbative approach in the conventional sense (expansion in the coupling constant) is not sufficient to gain a complete picture of QCD. Phenomena like the transition to quark-gluon plasma, colour-superconductivity and colour-flavour-locking are out of reach. But what can be done in order to gain some insights?

This is where non-perturbative QCD comes into play. On the one hand, there are traditional approaches, for example lattice QCD, where you assume that dynamics takes place on a discrete lattice and solve problems numerically. On the other hand, there are novel approaches like the so-called AdS/QCD duality, which is a manifestation of the AdS/CFT correspondence. It applies the holographic principle and maps a strongly coupled field theory (which is similar to QCD) to a string theory in its weak-coupling limit which allows for the treatment of problems which would be otherwise inaccessible.

This post imported from StackExchange Physics at 2014-08-29 16:49 (UCT), posted by SE-user Frederic Brünner
answered Sep 2, 2013 by Frederic Brünner (1,060 points) [ no revision ]
+ 2 like - 0 dislike

I don't get what you're asking?

What it means that non-perturbative QCD is the exploration of phases of quark matter, including the quark-gluon plasma?

Because, at high energies, you're at the so called asymptotic freedom regime. At this regime, your quarks interact weekly and the perturbative calculations are possible. And quark-gluon plasma is theoretically assumed to have been existed microseconds after the universe was created (because of high temperatures at the beginning of the 'Big Bang').

Also experiments such as ALICE at LHC in Cern and RHIC are studying the collisions that should, theoretically, produce quark-gluon plasma. A state, theoretically, where quarks and gluons are decoupled: since in nature, quarks are never on their own, they are either in mezon 'state' - two coupled quarks, or baryon 'state' - three coupled quarks (both part of hadrons - family of coupled quarks).

But it is still not clear how this happens, the mechanism behind it, and is this what they are seeing ate LCH indeed Q-G plasma.

My friend worked on ALICE, and he had a thesis from this feild. They are studying the impulse correlations in Pb-Pb collisions and they trying to see if the Q-G plasma state emerges from this collisions using Hanbury Brown and Twiss effect. That way, from correlations of two body wave functions you could deduce things about hadronization of quarks - since Q-G plasma exist only for a tiny amount of time, and quarks start to hadronize very quickly, you can only see that effect, and try to see if that effect really came from Q-G plasma. But it's still not clear if the Q-G plasma was created, and they're working hard to find that out.

Oh, also you have this QCD diagram

enter image description here

Which describes why you need high energies to produce Q-G plasma.

I hope this clears things a bit...

This post imported from StackExchange Physics at 2014-08-29 16:49 (UCT), posted by SE-user dingo_d
answered Sep 2, 2013 by dingo_d (110 points) [ no revision ]

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